5C2O4 + 2MnO4 + 16H → 2Mn + 10CO2 + 8H2O If 4 mL of 0.001 Μ KMnO4 solution is used to reactcompletely with 250 mL of saturated CaC2O4 solution according to the above reaction, what will be the Ksp of CaC2O4 under the same conditions?

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Answer 1 · 2018-03-08T11:32:25

$sf(K_(sp)=1.6xx10^(-9)color(white)(x)"mol"^2."l"^(-2))$

$sf(2MnO_4^(-)+16H^(+)+5C_2O_4^(2-)rarr2Mn^(2+)+8H_2O+10CO_2)$

$:.$ $sf("1mol"color(white)(x)Mn^(2+)-=5/2"mol"color(white)(x)C_2O_4^(2-))$

$sf(c=n/v)$

$:.$ $sf(n_(MnO_4^(-))=cxxv=0.001xx4/1000=4xx10^(-6))$

$:.$ $sf(n_(C_2O_4^(2-))=4xx10^(-6)xx5/2=10^(-5))$

$:.$ $sf([C_2O_4^(2-)]=10^(-5)/(0.250)=4xx10^(-5)color(white)(x)"mol/l")$

$sf(CaC_2O_4rightleftharpoonsCa^(2+)+C_2O_4^(2-))$

$sf(K_(sp)=[Ca^(2+)][C_2O_4^(2-)])$

$sf([Ca^(2+)]=[C_2O_4^(2-)])$

$:.$ $sf(K_(sp)=(4xx10^(-5))^(2)=1.6xx10^(-9)color(white)(x)"mol"^2."l"^(-2))$

I'll leave it to 2 sig. fig.