How do you solve for x in $6 x - 5 = 25$ $6x-5=25$ ?

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Answer 1 · 2018-03-08T17:28:06

$x = 5$ $x=5$

$6 x - 5 = 25$ $6x - 5 = 25$

First add $5$ $5$ on both sides

$6 x - 5 + 5 = 25 + 5$ $6x - 5 + 5 = 25 + 5$

$6 x = 30$ $6x = 30$

Divide both sides by $6$ $6$ .

$(cancel6x)/cancel6=30/6$

$x= 5$

How do you solve for x in 6x-5=256x−5=256x-5=25?