How do you solve $2(x-3)=(x-1)+7$ ?

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Answer 1 · 2018-03-09T23:05:52

$x=12$

$2(x-3)=(x-1)+7$

Distribute the left side

$(2)(x)+(2)(-3)=x-1+7$

$2x - 6 = x + 6$

Subtract $x$ on both sides

$2x - 6 - x = cancelx + 6 cancel(-x)$

$x - 6 = 6$

Finally, add $6$ on both sides

$x cancel(-6) cancel(+6) = 6+6$

$x=12$

How do you solve 2(x-3)=(x-1)+72(x-3)=(x-1)+7?