How do you solve #-5p + 16> 11#?

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Answer 1 · 2018-03-09T23:12:04

#p<1#

#-5p+16 >11#

Start by subtracting #16# from both sides

#-5p cancel(+16) cancel(-16) > 11 - 16#

#-5p > -5#

Then, divide both sides by #-5#

#(cancel(-5p))/cancel(-5)>(-5)/-5#

#p<1#

Note: When you are solving an inequality, you must change the sign if you divide both sides by a negative number.