How do you solve $15 (6 c - 1) - 4 = 88 c + 15$ $15( 6c - 1) - 4= 88c + 15$ ?

Question

1145 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-09T23:47:32

$c = 17$ $c=17$

$15 (6 c - 1) - 4 = 88 c + 15$ $15(6c-1)-4=88c+15$

Distribute

$(15) (16 c) + (15) (- 1) - 4 = 88 c = 15$ $(15)(16c)+(15)(-1)-4=88c=15$

$90 c - 15 - 4 = 88 c + 15$ $90c - 15 - 4 =88c +15$

$90 c - 19 = 88 c + 15$ $90c - 19 = 88c + 15$

Add $19$ $color(red)(19)$ to both sides

$90c cancel(-19) cancelcolor(red)(+19)= 88c + 15 + color(red)(19)$

$90c = 88c + 34$

Subtract $color(green)(88c)$ from both sides

$90c - color(green)(88c)= cancel(88c) + 34 cancelcolor(green)(-88c)$

$2c = 34$

Then divide both sides by $color(purple)(2)$

$(cancel2c)/cancelcolor(purple)(2)=34/color(purple)(2)$

$c=17$

How do you solve 15( 6c - 1) - 4= 88c + 1515(6c−1)−4=88c+1515( 6c - 1) - 4= 88c + 15?