How do you solve $2/-3=(4v+4)/(2v+14)$ ?

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Answer 1 · 2018-03-10T04:29:54

$v=(-5)/2$

$2/(-3)=(4v+4)/(2v+14)$

Cross multiply

$(2)(2v + 14)=(4v+4)(-3)$

Distribute

$(2)(2v)+(2)(14)=(-3)(4v)+(-3)(4)$

$4v + 28 + 12v = -12v - 12+12v$

$16v + 28 = -12$

$16v = -12 - 28$

$16v = -40$

Divide both sides by $16$

$(16v)/16 = (-40)/16$

$v=(-5)/2$

How do you solve 2/-3=(4v+4)/(2v+14)2/-3=(4v+4)/(2v+14)?