How do you evaluate #4( 20+ 12) \div ( 4- 3)#?

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Answer 1 · 2018-03-10T04:34:14

#128#

Using the order of operations, do the operations inside the parenthesis first, followed by multiplication/division and finally addition/subtraction.

Red operators indicate the current step.

#4(20color(red)+12)-:(4color(red)-3)#

#=4(32)-:(1)#

Multiply next (from left to right)

#=128-:1#

This is simply #128#