What is the equation of the line that has a slope of 2 and goes through (1,5)?

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Answer 1 · 2018-03-10T04:48:31

#y=2x+3#

Use the point-slope formula:

#y-y_1=m(x-x_1)#

Where:

#(x_1,y_1)# is a point on the graph

#m# is the slope

From the information given to us,

#(x_1,y_1)->(1,5)#

#m=2#

So...

#y-y_1=m(x-x_1)#
#" "darr#
#y-(5)=2(x-(1))#

To get into #y=mx+b# form, all we do is solve for #y#

#y-(5)=2(x-(1))#

#y-5=2x-2#

#y-5+5=2x-2+5#

#y=2x+3#

The graph of this is shown below:

graph{2x+3 [-10, 10, -5, 5]}