How do you evaluate #sqrt(16-x)# when x = 8?
1 Answer
Mar 10, 2018
Explanation:
First substitute 8 for x in the equation
Then simplify to get
This can be broken down into surd form to get
The square root of 4 is 2, but the square root of 2 is irrational, so can be left in surd form.
This leaves