How do you find the midpoint of (10,-3), (-8,-5)?

Question

1881 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-10T14:21:08

$(1,-4)$

Vertically: $(y_2 - y_1)=(y - y_1)$

$y_1+y_2=2y$

$y=(y_1+y_2)/2$

Horizontally: $(x_2-x_1)=(x-x_1)$

$x_1+x_2=2x$

$x=(x_1+x_2)/2$

$:.$ The coordinates of the midpoint $M(x,y)$ are given by:
$(x,y) = ((x_1+x_2)/2,(y_1+y_2)/2)$

$(x,y) = ((10+(-8) )/2,((-3)+(-5))/2)$

$(x,y) = ((2)/2,(-8)/2)$

$(x,y)$ = $(1$ , $-4)$