How do you solve $-38 = 2b+25-(-7b)$ ?

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Answer 1 · 2018-03-10T17:50:01

$color(red)(b=-7$

$-38=2b+25-(-7b)$

Subtracting 25 from both sides:

$-38-25=2b+7b$

$-63=9b$

Dividing both sides by 9

$-63/9=(9b)/9$

$color(red)(b=-7$

~Hope this helps! :)

How do you solve -38 = 2b+25-(-7b)-38 = 2b+25-(-7b)?