How do you solve the system x - 2y = 2 x2y=2 and x + y = 5x+y=5?

1 Answer
Mar 10, 2018

x = 4, y = 1x=4,y=1

Explanation:

The quickest way in this particular set is probably by substitution.

Rearranging the first equation,
x = 2y + 2x=2y+2

Substituting into the second equation,
2y + 2 + y = 52y+2+y=5

Collecting terms and rearranging
3y = 5-2 3y=52

That is
3y = 33y=3
which implies
y = 1y=1

Substituting this value for yy into the first equation
x - 2 = 2x2=2
which implies
x = 4x=4

It is always worth checking the solution, so substituting these values into the second equation gives
4 + 1 = 54+1=5 for the left hand side of the equation, which is equal to the right hand side of the equation, as expected.