How do you solve $4 y - 3 = 5 y + 2$ $4y-3=5y+2$ ?

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Answer 1 · 2018-03-11T09:39:54

y = -5

$4 y - 3 = 5 y + 2$ $4y - 3 = 5y + 2$

add 3 both sides

$4 y - 3 + 3 = 5 y + 2 + 3$ $4y - 3 + 3 = 5y + 2+3$
$4 y = 5 y + 5$ $4y = 5y + 5$

subtract 5y both sides

$4 y - 5 y = 5 y - 5 y + 5$ $4y - 5y = 5y - 5y + 5$
$- y = 5$ $- y = 5$

divide both side by -1

$- \frac{y}{- 1} = \frac{5}{- 1}$ $-y/-1 = 5/-1$
==> $y = - 5$ $y = -5$

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