How do you solve #x=4y# and #3x-2y=20# using substitution?

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Answer 1 · 2018-03-11T18:06:50

#x=8#

#y=2#

#x=4y" "# (let this be equation 1)

#3x-2y=20" "# (let this be equation 2)

So

#3x-2y=20#

#3(4y)-2y=20" "# (putting the value of #x# from equation1 in equation2)

#12y-2y=20#

#10y=20#

#y=2#

Therefore, from equation 1

#x = 4(2) = 8#