How do you solve $\frac{2}{3} n + 4 = 10 - \frac{4}{3} n$ $2/3n + 4 =10 - 4/3n$ ?

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How do you solve $\frac{2}{3} n + 4 = 10 - \frac{4}{3} n$ $2/3n + 4 =10 - 4/3n$ ?

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Answer 1 · 2018-03-11T18:23:12

n = 3

Explanation:

$\frac{2}{3} n + \frac{4}{3} n + 4 = 10 - \frac{4}{3} n + \frac{4}{3} n$ $2/3n + 4/3n + 4 = 10 - 4/3n + 4/3n$
$\frac{6}{3} n + 4 - 4 = 10 - 4$ $6/3n + 4 - 4 = 10 - 4$
$2 n = 6$ $2n = 6$
$n = 3$ $n = 3$

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How do you solve $\frac{2}{3} n + 4 = 10 - \frac{4}{3} n$ $2/3n + 4 =10 - 4/3n$ ?

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How do you solve $\frac{2}{3} n + 4 = 10 - \frac{4}{3} n$ $2/3n + 4 =10 - 4/3n$ ?