The sum of two numbers is 14 and the diference is 6 what are the two numbers?

2 Answers
Mar 11, 2018

a = 10 and b = 4a=10andb=4.

Explanation:

Let a be the larger and b be the smaller. We know that

a+b = 14 and a-b = 6a+b=14andab=6.

Solving the 2nd equation for a,

a = 6 + ba=6+b.

Substituting that expression for a in for the a in the first equation, and then solving for b,

6+b+b = 146+b+b=14

2*b = 14-6 = 82b=146=8

b = 8/2 = 4b=82=4
Therefore a = 6+4 = 10a=6+4=10.

I hope this helps,
Steve

Mar 11, 2018

1010 and 44.

Explanation:

Let's call the two numbers xx and yy. We know that x+y=14x+y=14 and x-y=6xy=6. We could guess and check, but there is an easier way. We can use elimination to solve for xx and yy, using *just these two equations! *


Why?
We can rewrite these two equations as 1x+1y=141x+1y=14 and 1x+(-1y)=61x+(1y)=6. Note that xx's coefficients are the same, so we can subtract the equations and xx will disappear, leaving us with the solution for yy. Also note that yy's coefficients are additive inverses, so we can add the equations and yy will disappear, giving us the solution for xx! That's both variables! Here we go:


Subtracting (solution for yy):
cancel(x)+y=14
cancel(x)-y=6
y-(-y)=8 y+y=8 2y=8 y=4 **So, one of the numbers is 4#.**

Adding (solution for x)
xcancel(+y)=14
xcancel(-y)=6
2x=20
x=10
So, the other number is 10.


Let's check:
x+y=14
10+4=14
14=14


x-y=6
10-4=6
6=6
We're good!

So, the two numbers are 10 and 4.