How do you solve $\frac{2}{3} x + 3 = x - 2$ $2/3x+3=x-2$ ?

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How do you solve $\frac{2}{3} x + 3 = x - 2$ $2/3x+3=x-2$ ?

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Answer 1 · 2018-03-11T21:22:38

$x = 15$ $x=15$

Explanation:

First let's get all like-terms on the same sides.
To do so, we can subtract 3 from both sides and subtract $x$ $x$ from both sides as well.

$\frac{2}{3} x + 3 - 3 - x = x - 2 - 3 - x$ $2/3x+3-3-x=x-2-3-x$

Simplify:
$\frac{2}{3} x - x = - 2 - 3$ $2/3x-x=-2-3$

Now we can combine like-terms:
$- \frac{1}{3} x = - 5$ $-1/3x=-5$

In order to isolate $x$ $x$ , multiply by -3 on both sides:
$- 3 \cdot - \frac{1}{3} x = - 5 \cdot - 3$ $-3*-1/3x=-5*-3$

Simplify:
$x = 15$ $x=15$

Answer 2 · 2018-03-11T21:24:13

$x = 15$ $x=15$

Explanation:

So the first thing you would want to do is to move the $\frac{2}{3} x$ $2/3x$ over to the right side of the equation, making it $- \frac{2}{3} x$ $-2/3x$ .

Subtract $x - \frac{2}{3} x$ $x-2/3x$ . Since the is no coefficient, $x$ $x$ means #3/3x, so

$x - \frac{2}{3} x = \frac{1}{3} x$ $x-2/3x = 1/3x$

Now move the whole number $- 2$ $-2$ to the left side, making it

$3 + 2 = 5$ $3 + 2 = 5$

Multiply both sides by $3$ $3$ to get $x$ $x$ alone.

$x = 15$ $x=15$

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How do you solve $\frac{2}{3} x + 3 = x - 2$ $2/3x+3=x-2$ ?

2 Answers

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