How do i solve this?

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How do i solve this?

$k x^{2} + x = x^{2} - 2$ $kx^2+x=x^2-2$

1 Answer

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Answer 1 · 2018-03-12T13:41:17

$x = \frac{- 1 \pm \sqrt{9 - 8 k}}{2 k - 2}$ $x=(-1+-sqrt(9-8k))/(2k-2)$

Explanation:

$k x^{2} + x = x^{2} - 2$ $kx^2+x=x^2-2$

Subtract $(x^{2} - 2)$ $(x^2-2)$ from both sides,

$k x^{2} - x^{2} + x + 2$ $kx^2-x^2+x+2$

Factorise the $x^{2}$ $x^2$ ,

$(k - 1) x^{2} + x + 2$ $(k-1)x^2+x+2$

Apply the quadratic formula,

$x = \frac{- 1 \pm \sqrt{1^{2} - 4 (k - 1) (2)}}{2 (k - 1)}$ $x=(-1+-sqrt(1^2-4(k-1)(2)))/(2(k-1))$
$x = \frac{- 1 \pm \sqrt{9 - 8 k}}{2 k - 2}$ $color(white)(x)=(-1+-sqrt(9-8k))/(2k-2)$

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How do i solve this?

$k x^{2} + x = x^{2} - 2$ $kx^2+x=x^2-2$

1 Answer

Explanation:

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Math

Humanities

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How do i solve this?

kx2+x=x2−2kx^2+x=x^2-2

1 Answer

Explanation:

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$k x^{2} + x = x^{2} - 2$ $kx^2+x=x^2-2$