What is x if #log_3(x) +log_2(x+6)=3#?

1 Answer
Mar 12, 2018

#1.18" "# approx

Explanation:

In general#" " log_b a" can be written as " loga/logb#

#log_3(x)+log_2(x+6)=3" can be written as " logx/log3+log (x+6)/log2=3#

#log2*logx+log3*log (x+6)=3log2*log3#

#logx^log2=log8^log3-log (x+6)^log3#

#logx^log2=log (8/(x+6))^log3#

Antilog both sides...

#x^log2=(8/(x+6))^log3#

I guess, it can be solved by graphing... desmos