How do you solve $3 x - \frac{2}{3} = \frac{5 x}{2} + 2$ $3x - \frac { 2} { 3} = \frac { 5x } { 2} + 2$ ?

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Answer 1 · 2018-03-12T19:49:52

$x = \frac{16}{3}$ $x = 16/3$

$3 x - \frac{2}{3} = \frac{5 x}{2} + 2$ $3x - 2/3 = (5x)/2 + 2$

Get all the $x$ $x$ terms on one side

$3 x - \frac{5 x}{2} = 2 + \frac{2}{3}$ $3x - (5x)/2 = 2 + 2/3$

Simplify

$\frac{x}{2} = \frac{8}{3}$ $x/2 = 8/3$

Multiply by $2$ $2$

And so $x = \frac{16}{3}$ $x = 16/3$

How do you solve 3x - \frac { 2} { 3} = \frac { 5x } { 2} + 23x−23=5x2+23x - \frac { 2} { 3} = \frac { 5x } { 2} + 2?