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Physics Question?

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Answer 1 · 2018-03-13T01:20:07

$T = 4.1$ $T=4.1$ $m$ $"m"$

Explanation:

We can simplify this problem to a pendulum, of length $3.8$ $3.8$ $m$ $"m"$ , swinging back and forth.

By doing this, the formula $T = 2 π \sqrt{\frac{L}{g}}$ $T = 2 pi sqrt(L/g)$ can be applied; where $T$ $T$ is the period, $L$ $L$ is the length, and $g$ $g$ is acceleration due to gravity.

Then, the period $T = 2 π$ $T=2 pi$ $\sqrt{\frac{3.8 m}{9.80665 m \cdot s^{- 2}}}$ $sqrt(frac(3.8 " m")(9.80665 " m" cdot "s"^(-2)))$

$\Rightarrow T = 4.0677273336$ $" " " " " " " " " Rightarrow T= 4.0677273336$ $m$ $"m"$

$" " " " " " " " " therefore T approx 4.1$ $"m"$

Therefore, the period of this swing would be around $4.1$ $"m"$ .

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