Differentiate with respect to x 1+1/x² ?

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Answer 1 · 2018-03-13T01:18:06

#f'(x) = -2/x^3#

#f(x) = 1+1/x^2#

#(df(x))/(dx) = d/(dx)(1) + d/(dx)1/x^2#

#f'(x) = 0 -2/x^3#

#f'(x) = -2/x^3#

Answer 2 · 2018-03-13T01:21:53

#-2/x^3#

#=d/dx(1+1/x^2)#
#=d/dx(1+x^-2)#
#=-2x^-3#
#=-2/x^3#