If i have 4.00 moles of gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

1 Answer

67.3"K"

Explanation:

Use the equation
PV=nRT

P= 5.6 "atm"= 5.6 xx 10^5 "Pa"
V=12 "L"=12/1000"m"^3
n=4"mol"
R=8.31 "J/mol" ( this is always constant)
T is unknown

By rearranging the equation....

T=(PV)/(nR)
Thus,
T=67.3 "K"