How do you solve #55> 7- 8x#?

1 Answer
F. Javier B.
Mar 13, 2018

See below

Explanation:

#55>7-8x# transposing

#8x>7-55#

#8x> -48#

#x> -48/8#

#x> -6#

The solution is all #x# bigger than -6. This is the same to interval #(-6,oo)#. Note that 6 is not in the interval because #x# must be bigger strictly than -6

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