What is the mass percent of Chlorine in the compound copper (II) chloride tetrahydrate?

Question

What is the mass percent of Chlorine in the compound copper (II) chloride tetrahydrate?

1 Answer

Impact of this question

1838 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-13T14:42:32

34.4%

Explanation:

Calculate the molar mass of compound $C u C l_{2} \cdot 4 H_{2} O$ $CuCl_2*4H_2O$ .
It is $206.5 \frac{g}{m o l}$ $206.5 g/(mol)$ .
Now find the mass of chlorine in this compound. There are two chlorine atoms in the compound, therefore $2 \cdot 35.5 = 71 \frac{g}{m o l}$ $2*35.5=71g/(mol)$

If $206.5 \frac{g}{m o l}$ $206.5 g/(mol)$ – 100%
then $71 \frac{g}{m o l}$ $71g/(mol)$ – x%

Cross multiply and get x = $34.4 %$ $34.4%$

Science

Math

Humanities

... and beyond

What is the mass percent of Chlorine in the compound copper (II) chloride tetrahydrate?

1 Answer

Explanation:

Related questions

Impact of this question