How do you find the domain and range of $y = \sqrt{x - 2}$ $y=sqrt(x-2)$ ?

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How do you find the domain and range of $y = \sqrt{x - 2}$ $y=sqrt(x-2)$ ?

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Answer 1 · 2018-03-13T22:21:53

The domain is $x - 2 \geq 0 \Rightarrow x \geq 2$ $x-2>=0=>x>=2$ hence $D_{f} = [2, + \infty)$ $D_f=[2,+oo)$ and the range is $y = \sqrt{x - 2} \geq 0 \Rightarrow y \geq 0$ $y=sqrt(x-2)>=0=>y>=0$ hence $R_{f} = [0, + \infty)$ $R_f=[0,+oo)$

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How do you find the domain and range of $y = \sqrt{x - 2}$ $y=sqrt(x-2)$ ?

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