How do you solve #-3( x - 5) ^ { 2} = - 18#?

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Answer 1 · 2018-03-14T17:26:11

Solution in explanation:

Expand #(x-5)^2#:

#-3[(x-5)(x-5)=-18#

#-3[x^2-10x+25]=-18#

Multiply by -3:

#-3x^2+30x-75=-18#

[Be careful of signs when multiplying.]

Adding #18# to both sides:

#-3x^2+30x-75+18=-18+18#

#-3x^2+30x-57=0#

Solve:

#x=5-##root#6# or x=5+##root#6