Question

What are the asymptotes and removable discontinuities, if any, of `f(x)= 1/x^2+2`?

Answer 1

Vertical Asymptote: `x=0`
Horizontal Asymptote: `y=0`

Explanation:

You can find a vertical asymptote
when you set the denominator equal to 0.

`x^2=0`
`x=0`
Therefore the vertical asymptote is 0.

Horizontal asymptote happens when the denominator has a higher degree or equal degree to the numerator. In this case the denominator has a higher degree then the numerator, so the is the horizontal asymptote is 0.