Physics. Work Problem?
A single force acts on a 2.5 kg particle-like object in such a way that the position of the object as a function of time is given by x = 3.8t - 1.7t2 + 0.95t3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 8.9 s.
my answer was 488.72 J but it was wrong.
A single force acts on a 2.5 kg particle-like object in such a way that the position of the object as a function of time is given by x = 3.8t - 1.7t2 + 0.95t3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 8.9 s.
my answer was 488.72 J but it was wrong.
1 Answer
Mar 15, 2018
Work done by an external force = change in kinetic energy.
Given,
So,
So,using this equation,we get,at
And at
So,change in kinetic energy =
Putting the given values we get,