Iron reacts with dilute sulfaric acid according to equation, Fe+H2SO4---> FeSO4+H2, What mass of iron will react with 75cm3 of 0.5 M H2SO4?

1 Answer
Mar 15, 2018

2.1grams of Fe

Explanation:

C = n/V

This implies, n = C*V

n(H2SO4) = 0.5 * 75/1000dm^3

n(H2SO4) = 0.0375 mol

from the chemical equation,

1mol of Fe reacts with 1mol of H2SO4

therefore 0.0375mol of H2SO4 will react with 0.0375mol of Fe

Also, n(Fe) = (m(Fe)/M(Fe))

M(Fe) = 56g/mol

m(Fe) = n(Fe)* M(Fe)

m(Fe) = 0.0375* 56

m(Fe) = 2.10grams