Question

What are all the zeroes of the function `f(x) = x^2-169`?

Answer 1

The zeroes of f(x) are `+-` 13

Explanation:

let f(x) = 0

`x^2` - 169 = 0

`x^2` = 169

take square root of both sides

`sqrt` `x^2` =`+-` `sqrt`169

x = `+-`13

`therefore`The zeroes of f(x) are `+-`13

Answer 2

`x=+-13`

Explanation:

`"to find the zeros set "f(x)=0`

`rArrf(x)=x^2-169=0`

`rArrx^2=169`

`color(blue)"take the square root of both sides"`

`rArrx=+-sqrt(169)larrcolor(blue)"note plus or minus"`

`rArrx=+-13larrcolor(blue)"are the zeros"`

Answer 3

`f(x)` has exactly two zeroes: `+13` and `-13`.

Explanation:

We call zero of a function to those values of `x` such that `f(x)=0`. We call also roots in polynomial functions.

In our case, we have to resolve `x^2-169=0`

Transposing terms, we have `x^2=169`. the square root of both sides give us

`sqrt(x^2)=x=+-sqrt(169)=+-13` because

`(+13)·(+13)=13^2=169` and
`(-13)·(-13)=(-13)^2=169`