How do you add (5x + y) + (4x + 2y)?

Question

1622 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-15T13:05:15

$(5 x + y) + (4 x + 2 y) = 5 x + y + 4 x + 2 y$ $(5x+y)+(4x+2y)= 5x+y+4x+2y$

$= (5 x + 4 x) + (y + 2 y)$ $= (5x+4x)+(y+2y)$

$= 9 x + 3 y$ $=9x+3y$

For this, we need to to add the x-coefficients and y-coefficients separately.

So I have first removed the brackets, since all the signs are positive, so there will be no change in any signs.

Then we add the x coefficients $5 x and 4 x$ $5x and 4x$ ,

which give us answer $9 x$ $9x$ .

Similarly, we add y-coefficients $y and 2 y$ $y and 2y$ ,

which give us answer $3 y . .$ $3y..$

Finally we get the answer as $9 x + 3 y$ $9x+3y$

Answer 2 · 2018-03-15T13:05:51

$(5 x + y) + (4 x + 2 y) = 9 x + 3 y$ $(5x+y)+(4x+2y)=color(red)(9x+3y)$

$(5 x + y) + (4 x + 2 y)$ $(color(blue)(5x)+color(lime)y)+(color(blue)(4x)+color(lime)(2y))$

can be re-arranged as
$XXX 5 x + 4 x + y + 2 y$ $color(white)("XXX")color(blue)(5x)+color(blue)(4x)+color(lime)(y)+color(lime)(2y)$

$XXX = 9 x + 3 y$ $color(white)("XXX")=color(blue)(9x)+color(lime)(3y)$