How do you write an equation in slope intercept form given that the line passes through the point (2,1) with slope -2/3?

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Answer 1 · 2018-03-15T21:24:37

#y = -2/3x + 7/3#

As slope is #-2/3# the equation reads like this:

#y=-2/3x +d#

So we must find #d#. For this we use the point (2,1), which means, that for #x=2# the value of #y=1#.

We fill it into the equation:

#1=-2/3*2 +d#

#1=-4/3 +d#

we add #4/3# on both sides of the equation:

#1+4/3=d#

#d=7/3#