How do you solve #-5( t - 5) + 8t = 5t - 2#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer seshani · Mahek ☮ Mar 16, 2018 #t=27/2 or13.5# Explanation: #-5(t-5)+8t=5t-2# #-5t+25+8t=5t-2# #-5t+8t-5t=-2-25# #-2t=-27# Divide both side by #2 # #-2t/2 = -27/2# #t=27/2 or t=13.5 # Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 2073 views around the world You can reuse this answer Creative Commons License