How do you factor #12xy+24xy^2+36xy^3#?

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Answer 1 · 2018-03-16T16:09:48

See below

To factorise we must factor out the Highest Common Factor of each term.

Here the HCFs of each term is #12# , #x# and #y#.

#therefore 12xy+24xy^2+36xy^3 = 12xy(1+2y+3y^2)#

When we expand it out we should get the same answer.

Answer 2 · 2018-03-16T16:25:00

#12xy(1+y(2+3y))#

At first take 12xy common out so,

#12xy(1+2y+3y^2#)

and then for the second 2 terms

#12xy(1+y(2+3y))#