How do you solve #(5x-3)/2=3x+8#?

1 Answer
Mar 17, 2018

#x=-19#

Explanation:

#(5x - 3)/2 = 3x + 8#

Let's get rid of the #2# in the denominator. No one likes fractions after all. So times # 2# on both sides.
On the right side, the #2# disappears, since #2 xx 1/2 = 1#. On the left side, #3x xx 2= 6x and 8 xx 2 = 16.#

Now you have:
#5x-3 = 6x + 16#

Subtract #5x# on both sides.

On the left side, we have #5x-5x = 0#. The right side is #6x - 5x = x#.

Now we have:
#-3 = x +16#

Subtract #16# on both sides so we can get #x#.

On the right side, we have #16 - 16 = 0#. On the left side, we have #-3 - 16 = -19.#

Therefore, #x = -19#.

Hope this helps! :)