How do you solve $\frac{5 x - 3}{2} = 3 x + 8$ $(5x-3)/2=3x+8$ ?

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How do you solve $\frac{5 x - 3}{2} = 3 x + 8$ $(5x-3)/2=3x+8$ ?

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Answer 1 · 2018-03-17T04:28:36

$x = - 19$ $x=-19$

Explanation:

$\frac{5 x - 3}{2} = 3 x + 8$ $(5x - 3)/2 = 3x + 8$

Let's get rid of the $2$ $2$ in the denominator. No one likes fractions after all. So times $2$ $2$ on both sides.
On the right side, the $2$ $2$ disappears, since $2 \times \frac{1}{2} = 1$ $2 xx 1/2 = 1$ . On the left side, $3 x \times 2 = 6 x and 8 \times 2 = 16 .$ $3x xx 2= 6x and 8 xx 2 = 16.$

Now you have:
$5 x - 3 = 6 x + 16$ $5x-3 = 6x + 16$

Subtract $5 x$ $5x$ on both sides.

On the left side, we have $5 x - 5 x = 0$ $5x-5x = 0$ . The right side is $6 x - 5 x = x$ $6x - 5x = x$ .

Now we have:
$- 3 = x + 16$ $-3 = x +16$

Subtract $16$ $16$ on both sides so we can get $x$ $x$ .

On the right side, we have $16 - 16 = 0$ $16 - 16 = 0$ . On the left side, we have $- 3 - 16 = - 19 .$ $-3 - 16 = -19.$

Therefore, $x = - 19$ $x = -19$ .

Hope this helps! :)

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