Given #csc^(2)(theta)=(7/2)# what is #cot^(2)(theta)#? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer sankarankalyanam · Jane Mar 17, 2018 #5/2# Explanation: Just apply the formula, #csc^2 theta - cot^2 theta=1# so,#cot^2 theta= csc^2 theta-1=7/2 -1=5/2# Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If #sec theta = 4#, how do you use the reciprocal identity to find #cos theta#? How do you find the domain and range of sine, cosine, and tangent? What quadrant does #cot 325^@# lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that #1+tan^2 theta = sec ^2 theta#? See all questions in Relating Trigonometric Functions Impact of this question 19682 views around the world You can reuse this answer Creative Commons License