How do you solve #12(5 + 2y) = 4y - (6 - 9y)#? Algebra Linear Equations Equations with Variables on Both Sides 2 Answers Ujjwal Mar 17, 2018 #y=-6# Explanation: #12(5+2y)=4y-(6-9y)# #=> 60+24y=4y-6+9y# #=> 60+24y=13y-6# #=> 24y-13y=-60-6# #=> 11y=-66# #=> y=-66/11# #=> y=-6# Answer link Jumbotron Mar 17, 2018 #y = -6# Explanation: #12(5 + 2y) = 4y - (6 - 9y)# #60 + 24y = 4y - 6 + 9y# #60 + 24y = 13y - 6# #24y - 13y = - 6 - 60# #11y = - 66# #(11y)/11 = - 66/11# #(cancel11y)/cancel11 = - 66/11# #y = -6# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 10114 views around the world You can reuse this answer Creative Commons License