How do you differentiate #g(x) = cos(5x) (x^2-4)# using the product rule? Calculus Basic Differentiation Rules Product Rule 1 Answer NJ Mar 17, 2018 #g^(')(x) = -5sin(5x)(x^2-4) + cos(5x)(2x)# Explanation: #g(x) = cos(5x)(x^2-4)# Product rule Applied: #g^(')(x) = -5sin(5x)(x^2-4) + cos(5x)(2x)# Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 1457 views around the world You can reuse this answer Creative Commons License