How do you subtract $\frac{13}{14 s} - \frac{11}{49 s}$ $\frac { 13} { 14s } - \frac { 11} { 49s }$ ?

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Answer 1 · 2018-03-17T18:30:43

$\frac{69}{98 s}$ $69/(98s)$

First we find common denominators. I did by multiplying each denominator to the other fraction. Should look like this

$\frac{(49) 13}{(49) 14 s} - \frac{(14) 11}{(14) 49 s}$ $((49)13)/((49)14s)-((14)11)/((14)49s)$

Then we get
$\frac{637}{686 s} - \frac{154}{686 s}$ $637/(686s)-154/(686s)$

$\frac{637 - 154}{686 s}$ $(637-154)/(686s)$

$\frac{483}{686 s}$ $483/(686s)$

There is a common multiple of $7$ $7$ between the numerator and denominator. So we then divide the numerator and denominator by $7$ $7$ , giving us

$\frac{69}{98 s}$ $69/(98s)$

How do you subtract 1314s−1149s\frac { 13} { 14s } - \frac { 11} { 49s }?