Question

How do you solve `3- 2( 5x - 4) > - 9` and `3x > - 4( x - 2)`?

Answer 1

`3-2(5x-4)> -9` ----------------- `3x> -4(x-2)`
`x<2` -----------------------------------`x>8/7`

Explanation:

Ok so the first one `3-2(5x-4)`
First we distribute the `-2` giving us
`3-10x+8> -9`

We now combine like terms on the left side
`11-10x> -9`

Subtract 11 on both sides giving us
`-10x> -20`

We now divide by `-10` on both sides.
REMEMBER: When dividing by a negative the sign always turn to the other side.

`(-10x)/(-10)< -20/(-10)`

`x<2`

Ok now the second one.
First we distribute the `-4` giving us
`3x> -4x+8`

Now we add `4x` on both sides giving us
`7x>8`

Now we divide `7` on both sides
`(7x)/7>8/7`

`x>8/7`