What volume of 0.125 M KMnO4 is required to yield 0.180 mol Of potassium permanganate KMnO4?

1 Answer
Mar 18, 2018

1.44 L

Explanation:

Recall that molarity is a measure of concentration in terms of moles of solute per volume of solution. Assuming that the we are using the standard units for molarity M=molesliters,

volume=0.180 mol KMnO40.125 M KMnO4= 1.44 L