How do you find slope of the line that contains (1,6) and (10, -9)?

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Answer 1 · 2018-03-18T09:54:45

Slope #= -5/3#

Recall the slope formula.

The given points are (1,6) and (10, -9)

comparing with #(x_1, y_1) and (x_2,y_2)#
#x_1=1##color(white)(dddddddddddddd##x_2=10#
#y_1=6##color(white)(dddddddddddddd##y_2=-9#

#m = (y_2 - y_1) / (x_2 - x_1)#

#m = (-9 - 6) / (10 - 1)#

#m = (-15) / (9)#

Slope= #-15/9 = -5/3#

Answer 2 · 2018-03-18T10:12:03

#m=-5/3#

#"Slope "(m) = (y_2-y_1)/(x_2-x_1)#

Here , #x_1=1#

#y_1=6#

#x_2=10#

#y_2=-9#

#=> m = (-9-6)/(10-1)#

#=> m = -15/9#

#=> m = -5/3#