What is the slope and y-intercept of the line 8y - 2x = -4?

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Answer 1 · 2018-03-18T10:30:22

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$8 y - 2 x = - 4$ $8y-2x=-4$

Convert it in the form of $y = m x + c$ $y=mx+c$

Here , $m$ $m$ is the slope of the line and $c$ $c$ is the $y$ $y$ -intercept.

$\Rightarrow 8 y = 2 x - 4$ $=> 8y=2x-4$

Divide by $2$ $2$ both sides

$\Rightarrow 4 y = x - 2$ $=> 4y=x-2$

$\Rightarrow y = \frac{1}{4} x - \frac{2}{4}$ $=> y=1/4 x -2/4$

$\Rightarrow y = \frac{1}{4} x - \frac{1}{2}$ $=> y=1/4 x -1/2$

On equating with $y = m x + c$ $y=mx+c$

$\Rightarrow m = \frac{1}{4} (Slope)$ $=> m=1/4 ("Slope")$

$\Rightarrow c = - \frac{1}{2} (y - intercept)$ $=> c=-1/2 (y-"intercept")$