How do you solve #-8x - 10 = 4x + 14#?
3 Answers
Explanation:
:.
multiply both sides by
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check:-
substitute
Explanation:
Move all variables to one side.
Explanation:
#"collect terms in x on the left and numeric values on the"#
#"right"#
#"subtract 4x from both sides"#
#-8x-4x-10=cancel(4x)cancel(-4x)+14#
#rArr-12x-10=14#
#"add 10 to both sides"#
#-12xcancel(-10)cancel(+10)=14+10#
#rArr-12x=24#
#"divide both sides by "-12#
#(cancel(-12) x)/cancel(-12)=24/(-12)#
#rArrx=-2#
#color(blue)"As a check"# Substitute this value into the equation and if the left side is equal to the right side then it is the solution.
#"left "=(-8xx-2)-10=16-10=6#
#"right "=(4xx-2)+14=-8+14=6#
#rArrx=-2" is the solution"#