How do you solve #-8x - 10 = 4x + 14#?

3 Answers
Mar 18, 2018

#x=-2#

Explanation:

#-8x-10=4x+14#

#:.=-8x-4x=14+10#

#:.-12x=24#

#:.-x=cancel24^2/cancel12^1#

:.#-x=2#

multiply both sides by#-1#

#:.-1xx-x=2xx-1#

#:.x=-2#

~~~~~~~~~~~~~

check:-

substitute #x=-2#

#-8(-2)-10=4(-2)+14#

#16-10=-8+14#

#6=6#

Mar 18, 2018

#x = -2#

Explanation:

#-8x - 10 = 4x + 14#

Move all variables to one side.

#-8x = 4x + 24#

#-12x = 24#

#x = -2#

Mar 18, 2018

#x=-2#

Explanation:

#"collect terms in x on the left and numeric values on the"#
#"right"#

#"subtract 4x from both sides"#

#-8x-4x-10=cancel(4x)cancel(-4x)+14#

#rArr-12x-10=14#

#"add 10 to both sides"#

#-12xcancel(-10)cancel(+10)=14+10#

#rArr-12x=24#

#"divide both sides by "-12#

#(cancel(-12) x)/cancel(-12)=24/(-12)#

#rArrx=-2#

#color(blue)"As a check"#

Substitute this value into the equation and if the left side is equal to the right side then it is the solution.

#"left "=(-8xx-2)-10=16-10=6#

#"right "=(4xx-2)+14=-8+14=6#

#rArrx=-2" is the solution"#