How do you solve $16 n - 20 \leq 2 (7 n + 10)$ $16n- 20\leq 2( 7n + 10)$ ?

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Answer 1 · 2018-03-18T14:59:50

$n \leq 20$ $n<=20$

$16 n - 20 \leq 2 (7 n + 10)$ $16n - 20 <= 2(7n +10)$

Distribute the left side

$16 n - 20 \leq (2) (7 n) + (2) (10)$ $16n - 20 <= (2)(7n)+(2)(10)$

$16 n - 20 \leq 14 n + 20$ $16n - 20 <= 14n + 20$

Then subtract $14 n$ $14n$ from both sides

$16 n - 20 - 14 n \leq 14 n + 20 - 14 n$ $16n - 20 - 14n <= 14n + 20 - 14n$

$2 n - 20 \leq 20$ $2n - 20 <=20$

Then add $20$ $20$ on both sides

$2 n - 20 + 20 \leq 20 + 20$ $2n - 20 + 20 <= 20 + 20$

$2 n \leq 40$ $2n <= 40$

Finally, divide both sides by 2

$\frac{2 n}{2} \leq \frac{40}{2}$ $(2n)/2 <= 40/2$

$n \leq 20$ $n<=20$

How do you solve 16n−20≤2(7n+10)16n- 20\leq 2( 7n + 10)?