How do you factor 108m3500?

1 Answer
Mar 18, 2018

=(3m5)(6m+5(1+3i))(6m+5(13i))

Explanation:

108=427=433
500=4125=453
So we have
4((3m)353)
Now we apply a3b3=(ab)(a2+ab+b2)
=4(3m5)(9m2+15m+25)
The quadratic factor can also be factored in factors
with complex numbers as follows :
disc : 1524925=675=2725=2752
m=15±527i18
m=5±53i6
m=(56)(1±3i)
9(m+(56)(1+3i))(m+(56)(13i))
So we get
36(3m5)(m+(56)(1+3i))(m+(56)(13i))
=(3m5)(6m+5(1+3i))(6m+5(13i))