How do you solve #x=-3y-14# and #x=y-3# using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer R0adkill · Stefan V. Mar 19, 2018 #x = 6.75# #y = -2.25# Explanation: Apply the substitution method: #x = -3y-12# #x = y -3# #-3y - 12 = y -3# Simplify #-4y = 9# #y = -9/4 = -2.25# So #x = -3y - 12# #x = -3(-9/4) - 12# #x = 6.75# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 2148 views around the world You can reuse this answer Creative Commons License