How do you simplify $(- 2x ^ { 2} y z ^ { 3} ) ( 2x ^ { 2} y ^ { 4} z ) ^ { 2}$ ?

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How do you simplify $(- 2x ^ { 2} y z ^ { 3} ) ( 2x ^ { 2} y ^ { 4} z ) ^ { 2}$ ?

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Answer 1 · 2018-03-19T23:10:54

$-8x^6 y^9 z^5$

Explanation:

First, square $2x^2 y^4 x$ to get $4x^4 y^8 z^2$ . Then, multiply it with $-2x^2 y x^3$ by combining $-2$ and $4$ to get $-8$ , $x^2$ and $x^4$ to get $x^6$ , $y$ and $y^8$ to get $y^9$ , and $z^3$ and $z^2$ to get $z^5$ . Combining all of these terms gets us $-8x^6 y^9 z^5$ .

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How do you simplify $(- 2x ^ { 2} y z ^ { 3} ) ( 2x ^ { 2} y ^ { 4} z ) ^ { 2}$ ?

1 Answer

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How do you simplify (- 2x ^ { 2} y z ^ { 3} ) ( 2x ^ { 2} y ^ { 4} z ) ^ { 2}(- 2x ^ { 2} y z ^ { 3} ) ( 2x ^ { 2} y ^ { 4} z ) ^ { 2}?

1 Answer

Explanation:

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How do you simplify $(- 2x ^ { 2} y z ^ { 3} ) ( 2x ^ { 2} y ^ { 4} z ) ^ { 2}$ ?