A series of integral based questions?
\intx^5\ln(x)dx
My answer: x^6/6(\ln(x)-1/6)+C
\int\sec^3(x)\tan(x)dx
My answer: 1/3\sec^3(x)+C
\int(x^3)/(x^2+1)dx
My answer: x^2/2-2\ln|x^2+1|+C
\int(5x)/(x^2-3x)dx
My answer: 5\ln|x-3|+C
- Find the area of the region bounded by
y=4-x^2 and y=2x+1 .
My answer: 27/3
- Find the volume of the region bounded by
y=x^3 , y=0 , and x=3 , revolved around the y-axis.
My answer: (243\pi)/5
- Approximate
\int_2^4\sqrt(x-2)dx using the Trapezoidal rule, rounding to 4 decimal places.
My answer: \approx1.8195
\int_1^\infty(\tan^-1(x))/(x^2+1)dx
My answer: divergent (\infty ) ?
\intx^5\ln(x)dx
My answer:x^6/6(\ln(x)-1/6)+C \int\sec^3(x)\tan(x)dx
My answer:1/3\sec^3(x)+C \int(x^3)/(x^2+1)dx
My answer:x^2/2-2\ln|x^2+1|+C \int(5x)/(x^2-3x)dx
My answer:5\ln|x-3|+C - Find the area of the region bounded by
y=4-x^2 andy=2x+1 .
My answer:27/3 - Find the volume of the region bounded by
y=x^3 ,y=0 , andx=3 , revolved around the y-axis.
My answer:(243\pi)/5 - Approximate
\int_2^4\sqrt(x-2)dx using the Trapezoidal rule, rounding to 4 decimal places.
My answer:\approx1.8195 \int_1^\infty(\tan^-1(x))/(x^2+1)dx
My answer: divergent (\infty ) ?
1 Answer
Mar 20, 2018
1 - 4 check by differentiating.
Explanation:
5) is incorrect
6) I get the same answer
8) converges